Subject: Re: [xsl] Want to print elements/attrib specified by an XPath that is passed as a param From: ac <ac@xxxxxxxxxxxxx> Date: Tue, 16 Jun 2009 00:21:07 -0400 |
Cheers, ac
On Mon, Jun 15, 2009 at 08:04:48PM -0700, John Christopher wrote:
My goal: I want an XSLT stylesheet that displays the contents
of any element or attribute whose name I pass to the stylesheet
as an XPath via a param.
[...]
There are three main approaches I can think of here.
(1) write an XSLT stylesheet that generates a new stylesheet in which those XPath fragments (or template match patterns) are in fact hard-coded...
(2) use the eval extension in an implementation that provides it
(3) interpret the XPath expression in XSLT.
E.g. <xsl:template match="*"> <xsl:param name="name" />
<xsl:if test="localname() = $name"> <xsl:message>got one!</xsl:message> </xsl:if> <xsl:apply-templates /> </xsl:template>
Well, this doesn't handle a/b, but you could use substring-after to handle that, or, in XSLT 2, you could split the string on "/" and then look for predicates, and you could do fancy things with count() to sort into document rder & weed out duplicates.
But I'd favour approach (1) probably.
Liam
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