Re: [xsl] returning nodes which have a specific child

[Michael Ludwig <mlu@xxxxxxxxxxxxx>]

David Carlisle schrieb:

> You can see that the node test node() is true for  attribute nodes if
> you apply it to an axis that has such nodes, as in:
>
> attribute:node()

To further clarify or mystify or nodify all this node salad, here's an
alternative, more symmetrical syntax for our beloved identity template:

  <xsl:template match="@node()|node()">
    <xsl:copy>
      <xsl:apply-templates select="@node()|node()"/>
    </xsl:copy>
  </xsl:template>

This probably has been proposed before, but I haven't seen it yet.

Interestingly (and regrettably), LibXSLT 1.1.24 will compile this in the
path expression (@select), but not in the match pattern.

  xsltCompilePattern : failed to compile '@node()'

(Yes, I'm going to notify Daniel.)

> node() matches attributes in other contexts too, such as the xpath2
> expression
>
> @foo instance of node()

Great test - I'd never have thought of that.

Michael Ludwig