Re: [xsl] Combining segments by matching attributes

[Martin Honnen <Martin.Honnen@xxxxxx>]

Dot Porter wrote:

> <group>
>   <text xml:id="A15">
>     <seg n="220.2">...</seg>
>     <seg n="220.3">...</seg>
>     (etc.)
>   </text>
>   <text xml:id="B15">
>     <seg n="220.2">...</seg>
>     <seg n="220.3">...</seg>
>     (etc.)
>   </text>
> </group>
>
> The texts may or may not have all the same segments (so text A may
> have seg[@n='223.1'] and text B may not, or vice versa). In addition
> the numbers are not unique to each segment (there may be several segs
> in a row with the same number).
>
> Given this, I would like to generate a file that pulls together the
> like segments from each text, resulting in something that looks like
> this:
>
> <app>
>   <rdg wit="#A15"><seg n="220.2">...</seg></rdg>
>   <rdg wit="#B15><seg n="220.2">...</seg></rdg>
>   (etc.)
> </app>
> <app>
>   <rdg wit="#A15"><seg n="220.3">...</seg></rdg>
>   <rdg wit="#B15><seg n="220.3">...</seg></rdg>
>   (etc.)
> </app>
> <app>
>   <!-- for example, A15 lacks seg[@n='223.1'] -->
>   <rdg wit="#B15"><seg n="223.1">...</seg></rdg>
>   (etc.)
> </app>

Here is an XSLT 2.0 solution:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  version="2.0">

  <xsl:output method="xml" indent="yes"/>

  <xsl:template match="/">
    <xsl:for-each-group select="group/text/seg" group-by="@n">
      <app>
        <xsl:apply-templates select="current-group()"/>
      </app>
    </xsl:for-each-group>
  </xsl:template>

  <xsl:template match="seg">
    <reg wit="#{../@xml:id}">
      <xsl:copy-of select="."/>
    </reg>
  </xsl:template>

</xsl:stylesheet>




--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/