RE: [xsl] Help on XSL to tranform simple flat xml sequential

In XSLT 2.0 you can do

<xsl:for-each-group select="*" group-starting-with="para[@role='title']">
  <paragraph>
    <xsl:apply-templates select="current-group()"/>
  </paragraph> 
</xsl:for-each-group>

In 1.0 it's rather harder - google for "XSLT positional grouping".

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 
 

> -----Original Message-----
> From: Christian Oshiro [mailto:chris_oshiro@xxxxxxxxx] 
> Sent: 30 August 2009 17:08
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Help on XSL to tranform simple flat xml sequentially
> 
> This seems like a pretty simple thing to do, but I usually 
> rely on nested xml. How can I tranform xml that looks like this:
> 
> <para role=title>main title1</para>
> <para role=subtitle>subtitle1</para>
> <para>This is the body of the paragraph. 1</para> <list>some 
> stuff 1</list> <para role=title>main title2</para> <para 
> role=subtitle>subtitle2</para> <para>This is the body of the 
> paragraph. 2</para> <list>some stuff 2</list> <para 
> role=title>main title3</para> <para 
> role=subtitle>subtitle3</para> <para>This is the body of the 
> paragraph. 3</para> <list>some stuff 3</list>
> 
> I'd like to transform this using xlst to something like this:
> 
> <paragraph>
>   <title>main title1</title>
> 
> <subtitle>subtitle1</subtitle>
> 
> <body>This is the body of the paragraph. 1</body>
> 
> <list>some stuff 1</list>
> </paragraph>
> <paragraph>
>   <title>main title2</title>
>   <subtitle>subtitle2</subtitle>
>   <body>This is the body of the paragraph. 2</body>
>   <list>some stuff 2</list>
> </paragraph>
> <paragraph>
>   <title>main title3</title>
>   <subtitle>subtitle3</subtitle>
>   <body>This is the body of the paragraph. 3</body>
>   <list>some stuff 3</list>
> </paragraph>
> 
> So i need to go node by node and test when role=title shows 
> up. Thanks for the insight.

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RE: [xsl] Help on XSL to tranform simple flat xml sequentially