Re: [xsl] Help on XSL to tranform simple flat xml sequential

Christian Oshiro wrote:

This seems like a pretty simple thing to do, but I usually rely on nested xml. How can I tranform xml that looks like this:

<para role=title>main title1</para>
<para role=subtitle>subtitle1</para>
<para>This is the body of the paragraph. 1</para>
<list>some stuff 1</list>
<para role=title>main title2</para>
<para role=subtitle>subtitle2</para>
<para>This is the body of the paragraph. 2</para>
<list>some stuff 2</list>
<para role=title>main title3</para>
<para role=subtitle>subtitle3</para>
<para>This is the body of the paragraph. 3</para>
<list>some stuff 3</list>

I'd like to transform this using xlst to something like this:

<paragraph>
  <title>main title1</title>

<subtitle>subtitle1</subtitle>

<body>This is the body of the paragraph. 1</body>

<list>some stuff 1</list>
</paragraph>
<paragraph>
  <title>main title2</title>
  <subtitle>subtitle2</subtitle>
  <body>This is the body of the paragraph. 2</body>
  <list>some stuff 2</list>
</paragraph>
<paragraph>
  <title>main title3</title>
  <subtitle>subtitle3</subtitle>
  <body>This is the body of the paragraph. 3</body>
  <list>some stuff 3</list>
</paragraph>

So i need to go node by node and test when role=title shows up. Thanks for the insight.

Here is an XSLT 2.0 stylesheet:


<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  version="2.0">

<xsl:output indent="yes"/>

<xsl:template match="doc"> <xsl:copy> <xsl:for-each-group select="*" group-starting-with="para[@role = 'title']"> <paragraph> <xsl:apply-templates select="current-group()"/> </paragraph> </xsl:for-each-group> </xsl:copy> </xsl:template>

  <xsl:template match="para[@role = 'title']">
    <title><xsl:apply-templates/></title>
  </xsl:template>

  <xsl:template match="para[@role = 'subtitle']">
    <subtitle><xsl:apply-templates/></subtitle>
  </xsl:template>

  <xsl:template match="para[not(@role)]">
    <body><xsl:apply-templates/></body>
  </xsl:template>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/

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Re: [xsl] Help on XSL to tranform simple flat xml sequentially