Subject: Re: [xsl] Seed problem in FXSL randomizeList From: Jesper Tverskov <jesper.tverskov@xxxxxxxxx> Date: Wed, 7 Oct 2009 11:50:50 +0200 |
Thanks for the hint Michael. I now do this for the first seed: xs:integer(format-time(current-time(), '[s][f]')) The sequence of positions returned is then kept in a variable x like this: <xsl:variable name="x"> <xsl:call-template name="randomizeList"> <xsl:with-param name="pList" select="(1 to count(/items/item))[. != $num]"/> <xsl:with-param name="pSeed" select="$pSeed" as="xs:integer"/> </xsl:call-template> </xsl:variable> The second seed is then generated like this: xs:integer(substring(string-join($x/el[position() < 6], ''), 1, 4)) Etc, and again for the third seed, etc, and it looks like it works well. I'm now more confident that the pseudo-randomization is random! Cheers, Jesper http://www.xmlplease.com
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