Subject: Re: [xsl] reading files from directory and returning the same name to output directory From: Andrew Welch <andrew.j.welch@xxxxxxxxx> Date: Mon, 30 Nov 2009 15:05:06 +0000 |
2009/11/30 a kusa <akusa8@xxxxxxxxx>: > Hi > > Here is my requirement. > > Read XML files from an input directory. > The results must be in another output directory. But the names of the > result xml files must be the same as the input xml files. > > How do I do this with XSLT 2.0? You could: - use the directory tab of Kernow (http://kernowforsaxon.sf.net/) - or you could use Saxon directly from the command line - or you could write a standalone transform that uses the collection() function and xsl:result-document. -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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