Re: [xsl] reading files from directory and returning the same name to output directory

Subject: Re: [xsl] reading files from directory and returning the same name to output directory
From: Andrew Welch <andrew.j.welch@xxxxxxxxx>
Date: Mon, 30 Nov 2009 15:05:06 +0000
2009/11/30 a kusa <akusa8@xxxxxxxxx>:
> Hi
>
> Here is my requirement.
>
> Read XML files from an input directory.
> The results must be in another output directory. But the names of the
> result xml files must be the same as the input xml files.
>
> How do I do this with XSLT 2.0?

You could:

- use the directory tab of Kernow (http://kernowforsaxon.sf.net/)
- or you could use Saxon directly from the command line
- or you could write a standalone transform that uses the collection()
function and xsl:result-document.




-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

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