Re: [xsl] reading files from directory and returning the same name to output directory

[a kusa <akusa8@xxxxxxxxx>]

Thank you very much Andrew. This is a pretty cool tool and works great!

On Mon, Nov 30, 2009 at 9:05 AM, Andrew Welch <andrew.j.welch@xxxxxxxxx>
wrote:
> 2009/11/30 a kusa <akusa8@xxxxxxxxx>:
>> Hi
>>
>> Here is my requirement.
>>
>> Read XML files from an input directory.
>> The results must be in another output directory. But the names of the
>> result xml files must be the same as the input xml files.
>>
>> How do I do this with XSLT 2.0?
>
> You could:
>
> - use the directory tab of Kernow (http://kernowforsaxon.sf.net/)
> - or you could use Saxon directly from the command line
> - or you could write a standalone transform that uses the collection()
> function and xsl:result-document.
>
>
>
>
> --
> Andrew Welch
> http://andrewjwelch.com
> Kernow: http://kernowforsaxon.sf.net/