Re: [xsl] want to display sum of every two records

["Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx>]

Dear Kumar,

If your input looks like

<?xml version="1.0" encoding="utf-8"?>
<doc>
  <mezo eazon="AA">200</mezo>
  <mezo eazon="AA">50</mezo>
  <mezo eazon="AA">300</mezo>
  <mezo eazon="AA">50</mezo>
</doc>

you may transform it using the following XSLT (2.0):

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  version="2.0"  >

  <xsl:output
    method="xml"
    indent="yes"
    />

  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

  <xsl:template match="doc">
    <xsl:copy>
      <xsl:for-each-group select="*"
        group-starting-with="*[position() mod 2 = 1]">
        <xsl:copy-of select="current-group()" />
        <mezo eazon="BB">
          <xsl:value-of select="sum(current-group())"/>
        </mezo>
      </xsl:for-each-group>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>


Gerrit


On 22.02.2010 09:09, anil kumar wrote:
> Hi,
>
>   want to display the column BB as sum of  every two records
>
> my o/p should be like below..
>
> <mezo eazon="AA">200</mezo>
> <mezo eazon="AA">50</mezo>
> <mezo eazon="BB">250</mezo>
> <mezo eazon="AA">300</mezo>
> <mezo eazon="AA">50</mezo>
> <mezo eazon="BB">350</mezo>
>
> iam breaking my head to get the above o/p.
>
> any suggestions ..Can you get it through XSL
>
> Thanks
> Kumar

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Gerrit Imsieke
Geschdftsf|hrer / Managing Director
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gerrit.imsieke@xxxxxxxxx, http://www.le-tex.de

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