Re: [xsl] set union? xslt 2.0

[Dave Pawson <davep@xxxxxxxxxxxxx>]

On Thu, 8 Apr 2010 11:08:45 +0100
Andrew Welch <andrew.j.welch@xxxxxxxxx> wrote:

> > Still leaves one side with a string...
> 
> Sure, but that's "the right way" to represent that in XML, then you
> can just pass in your delimited parameter and do:
> 
> select="skillarea[targets/target = $targets]"
> 
> where $targets is a top level variable created when you tokenize the
> param into a sequence of items.

Sneaky Andrew!
   tokenized param as="item()*"= element value.
Yes, that works. 
Thanks. 

I've now got Davids idea working. 

<xsl:apply-templates
select="skillarea[tokenize(@targets,'\|')=tokenize($targets,'\|')]"/>

since it's a regex, | needs escaping.

More than one way to skin a cat?

Thanks.




-- 

regards 

-- 
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk