Subject: Re: [xsl] EXSLT replace to XSLT 2.0 replace From: Wolfgang Laun <wolfgang.laun@xxxxxxxxx> Date: Wed, 14 Apr 2010 10:48:07 +0200 |
Omit the 'g', which replace() does anyway. Omit the '(?: ... )" from the regular expression. (This is uncounted grouping, which isn't important here. The | in (\p{Lu}|\p{Ll}] looks suspicious. These are alternatives, anyway, within [] -W On Wed, Apr 14, 2010 at 9:48 AM, Szabo, Patrick (LNG-VIE) <patrick.szabo@xxxxxxxxxxxxx> wrote: > Hi, > > I'm using Saxon 9 and XSLT 2.0 > > I'm currently updateing a few 1.0 Stylesheets to 2.0. > In one of those Stylesheets i've found this: > > <xsl:value-of select="regexp:replace(., > '(?:(.+@.+\.[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))', 'g', > '$1$2$3')"/> > > Is there a way to to that in 2.0 without EXSLT ?! > I - of course - wanted to try it with replace() but i cant seem to > figure it out. > > best regards... > > Patrick Szabo > XSLT-Entwickler > > Tel.: +43 (1) 534 52 - 1573 > Fax: +43 (1) 534 52 - 146 > > Patrick.Szabo@xxxxxxxxxxxxx > > LexisNexis Verlag ARD Orac GmbH & Co KG > Marxergasse 25, 1030 Wien > FN 8333f, Handelsgericht Wien > http://www.lexisnexis.at/
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