AW: [xsl] EXSLT replace to XSLT 2.0 replace

["Szabo, Patrick \(LNG-VIE\)" <patrick.szabo@xxxxxxxxxxxxx>]

Thx for your response.

I think grouping is important here because the 4th argument is the string that
should be replaced with.
In this argument are references to regex-groups...i'm not sure about that but
i think so.
If i remove the (?: the group numbers will change won't they ?!

regards


Patrick Szabo
 XSLT-Entwickler

Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146

Patrick.Szabo@xxxxxxxxxxxxx

LexisNexis Verlag ARD Orac GmbH & Co KG
Marxergasse 25, 1030 Wien
FN 8333f, Handelsgericht Wien
http://www.lexisnexis.at/

-----UrsprC<ngliche Nachricht-----

Von: Wolfgang Laun [mailto:wolfgang.laun@xxxxxxxxx]
Gesendet: Mittwoch, 14. April 2010 10:48
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: Re: [xsl] EXSLT replace to XSLT 2.0 replace

Omit the 'g', which replace() does anyway.

Omit the '(?: ... )" from the regular expression. (This is uncounted
grouping, which isn't important here.

The | in  (\p{Lu}|\p{Ll}]  looks suspicious. These are alternatives,
anyway, within []

-W

On Wed, Apr 14, 2010 at 9:48 AM, Szabo, Patrick (LNG-VIE)
<patrick.szabo@xxxxxxxxxxxxx> wrote:
> Hi,
>
> I'm using Saxon 9 and XSLT 2.0
>
> I'm currently updateing a few 1.0 Stylesheets to 2.0.
> In one of those Stylesheets i've found this:
>
> <xsl:value-of select="regexp:replace(.,
> '(?:(.+@.+\.[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))', 'g',
> '$1$2$3')"/>
>
> Is there a way to to that in 2.0 without EXSLT ?!
> I - of course - wanted to try it with replace() but i cant seem to
> figure it out.
>
> best regards...
>
> Patrick Szabo
>  XSLT-Entwickler
>
> Tel.: +43 (1) 534 52 - 1573
> Fax: +43 (1) 534 52 - 146
>
> Patrick.Szabo@xxxxxxxxxxxxx
>
> LexisNexis Verlag ARD Orac GmbH & Co KG
> Marxergasse 25, 1030 Wien
> FN 8333f, Handelsgericht Wien
> http://www.lexisnexis.at/