Re: [xsl] Could not use matches in Regular Expression (XSLT 2.0)

[Wolfgang Laun <wolfgang.laun@xxxxxxxxx>]

The pattern must be a string, so enclose it in apostrophes. (Also,
there is one opening bracket missing.) To have an exact match, use '^'
and '$' to anchor at the beginning and the end. You may simplify using
a repeat count (and \d for digit). All together now:

   matches( ., '^4\d{6}$' )

-W

> On Sat, May 1, 2010 at 3:56 PM, Jack Bush <netbeansfan@xxxxxxxxxxxx> wrote:
>>
>> Hi Forum members,
>>
>> I
>> am new to XSLT 2.0 and would like to do the following basic numeric string
pattern
>> matching using regular expression:
>>
>> <xsl:template match="ns:p[ns:strong='Telephones:']">
>>  <xsl:choose>
>>    < -- If global parameter $TELEPHONE_AREA_CODE equals to FAIRYLAND -->
>>    <xsl:when test="$TELEPHONE_AREA_CODE = ''FAIRYLAND">
>>      <xsl:for-each select="ns:a">
>>      <-- Only accept the phone number that starts with 4 follow by six
digits....   --->
>>        <xsl:if test="matches(.,4[0-9][0-9][0-9]0-9][0-9][0-9])">
>>          <phone_number><xsl:value-of select='.'/></phone_number>
>>        </xsl:if>
>>      </xsl:for-each>/>
>>  ......
>>
>> However, it is picking up phone numbers starting with 1 instead. Also tried
the starts-with() with the same outcomes.
>>
>> I am using JDK1.6.19, Netbeans 6.7, JDOM 1.1, Saxon 9.1 on Windows XP.
>>
>> Your assistance would be much appreciated.
>>
>> Thanks in advance,
>>
>> Jack