Subject: [xsl] Moving or removing a period From: "Flanders, Charles E (US SSA)" <charles.flanders@xxxxxxxxxxxxxx> Date: Tue, 18 May 2010 15:05:13 -0400 |
I need some help moving a period from one context to another. I can identify where period needs to be inserted but I can't get rid of the existing period. Here's what a I have so far <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <xsl:include href="copy.xsl"/> <xsl:template match="prompt"> <xsl:if test="parent::link/following-sibling::text() ='.'"> <prompt> <xsl:value-of select="."/><xsl:text>.</xsl:text> </prompt> </xsl:if> </xsl:template> A snippet of the pertinent XML looks something like this: (there's a whole lot more to this document, hence the "copy.xsl" include). <para> <link linkaction="prompt" linktype="goto" xlink:href="IETM://M00206" xmlns:xlink="http://www.w3.org/1999/xlink" xreftype="wp"> <prompt>This is the content stuff</prompt> </link>. </para> I can get the period into the <prompt> element but I can't seem to find a good way to eliminate the period after the <link> end tag. I cannot perform a simple search and replace because there are cases when a <link> element does NOT have a child <prompt> element, so that period needs to remain. I only want to eliminate "." when <link> contains a child <prompt>. The parent of <link> is usually either <para> or <trim.para>. C Flanders
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