Re: [xsl] Find the Position Index of Elements‏‏

Subject: Re: [xsl] Find the Position Index of Elements‏‏
From: David Carlisle <davidc@xxxxxxxxx>
Date: Sun, 13 Jun 2010 22:48:51 +0100
On 13/06/2010 20:43, Alice Wei wrote:

I have an XML snippet as in the following:

     <title>(I Just) Died In Your Arms</title>
     <album>80 Popular Hits</album>
     <artist>Cutting Crew</artist>
     <date added="03-24-2009"/>

This is one of the songs out of categories I have in my xml file, and
currently I use XPath expression as in the following:
/music_songs/song[category='Rock' as an example to find all the songs
in the Rock category.

whenever you use /a/b/c/[something='zzz']

you should think of doing


instead, it can be surprising the speedup you can get

I need to also be able to pull the position index of the song elements that I pull from the above expression, and use that in VB.NET for process. I tried using count(), position(), but they seem to be able to detect, but they cannot give me a list like

you don;t say if you are using xslt 1 or 2.

xslt 1 doesn't have a datatype that can store a sequence of integers.
You can get the numbers as for example

<xsl:for-each select="/music_songs/song[category='Rock']">

and then use


or <xsl:value-of select="count(preceding-sibling::song[category='Rock'])+1)"/>

Ib xslt2 you can store a list of integers


for example would work (although is paerhaps rather inefficient)


Current Thread