[xsl] Selecting all elements which have an attribute that matches a given pattern

Subject: [xsl] Selecting all elements which have an attribute that matches a given pattern
From: "Etheridge, Stephen" <stephen.etheridge@xxxxxxxxxx>
Date: Wed, 18 Aug 2010 08:57:36 +0100
Hi all and apologies if this has been dealt with previously, I searched
the archives and FAQ but did not find anything that was close to my
problem:

I have an XML file (a schema in fact) that is many thousands of lines
long and I need to edit it (i.e transform it).  There are numerous
elements of type <xs:element> all of which have a "name" attribute.
Some of those name attributes end with the string "List", e.g.
"MilkTypeList".  For those elements, I want to apply a template to add
an additional <xs:element>.  I am having great trouble crafting the
correct "match" for my <xsl:template>.  I have tried contains() and
matches() but my editor (Oxygen) states that those cannot be used as a
pattern and my reading supports that.  Can anyone help?

Thanks

Stephen



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