Re: [xsl] Why does the addition of one (1) to a positiveInteger produce an integer?

["Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx>]

Try casting each numerical argument to xs:positiveInteger:

On 29.08.2010 21:43, Costello, Roger L. wrote:
>      <xsl:sequence select="f:iter($count + 1)" />

<xsl:sequence select="f:iter($count + xs:positiveInteger(1))" />

(also when invoking f:iter outside the recursion).

> What is the rationale for this? After all, if I add one (1) to any positiveInteger the result must be a positiveInteger.

Maybe the XSLT processor isn't smart enough. It just seems to adhere to 
the rule "positiveInteger + integer = integer". I'm not sure whether 
it's worth the while to make the processor look at the values rather 
than just at the types before applying implicit typecasts.

-Gerrit



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