Subject: RE: [xsl] default template ? From: "Fabien Tillier" <f.tillier@xxxxxxxx> Date: Mon, 27 Sep 2010 17:55:12 +0200 |
Thanks Michael. It is clearer now (I answered first to Andrew because your e-mail fall into my spam filter...) Best regards, Fabien -----Message d'origine----- De : Ludwig, Michael [mailto:Michael.Ludwig@xxxxxxxxxxxx] Envoyi : lundi 27 septembre 2010 17:41 @ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx Objet : RE: [xsl] default template ? > I was wondering how an XSL Stylesheet can be done to treat > all nodes in an XML file if a template doesn't fit. Two examples. The copy template: <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> A (warning) message template: <xsl:template match="@*|node()"> <xsl:message> <xsl:value-of select="concat( '# ', name(), ' ' )"/> <xsl:apply-templates select="@*|node()"/> </xsl:message> </xsl:template> You can think up your own default action. Default matching is: <xsl:template match="@*|node()"> Michael
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