Subject: RE: [xsl] default template ? From: "Fabien Tillier" <f.tillier@xxxxxxxx> Date: Mon, 27 Sep 2010 17:56:43 +0200 |
Thank you Ken. I think it is a very basic question.... Regards, Fabien -----Message d'origine----- De : G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx] Envoyi : lundi 27 septembre 2010 17:53 @ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx Objet : Re: [xsl] default template ? At 2010-09-27 17:27 +0200, Fabien Tillier wrote: >I was wondering how an XSL Stylesheet can be done to treat all nodes in >an XML file if a template doesn't fit. >I mean, if an xml is like ><Row> > <A>A value</A> > <B>B value</B> > <C>C value</C> ></Row> > >If I get one template for treating <A> nodes (match = "A"), and one for ><B> nodes, I would like to have some kind of fall back template for the >C nodes which don't have a specific one. >Is this possible ? Certainly ... the XPath for an element of any name is "*". The XPath for a node of any time is "node()". So, for what you want: <xsl:template match="*"> ... any element not matched elsewhere ... </xsl:template> I hope this helps. . . . . . . . . . . . . Ken -- XSLT/XQuery training: after http://XMLPrague.cz 2011-03-28/04-01 Vote for your XML training: http://www.CraneSoftwrights.com/s/i/ Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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