Subject: Re: [xsl] dateTime conversion From: sudheshna iyer <sudheshnaiyer@xxxxxxxxx> Date: Sun, 3 Oct 2010 16:35:22 -0700 (PDT) |
Michael, I am using xslt 1.0. I guess I need to find more from requirements. My xsd has xs:datetime variable but I am receiving "2010-10-03T18:15:20-0400" from my client and hence the validation is failing. In xmlspy, if I auto generate the xml from xsd, sample value for xs:datetime is in format "2001-12-17T09:30:47Z". So I thought I might have to convert "2010-10-03T18:15:20-0400" to format "2001-12-17T09:30:47Z". But the number in the TO format is just a sample. I am not sure what is the efficient way to convert date that is in format "2010-10-03T18:15:20-0400" to format "2001-12-17T09:30:47Z" --- On Sun, 10/3/10, Michael Kay <mike@xxxxxxxxxxxx> wrote: > From: Michael Kay <mike@xxxxxxxxxxxx> > Subject: Re: [xsl] dateTime conversion > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Date: Sunday, October 3, 2010, 7:07 PM > > > Please ignore the portion that is before the timezone > and convert > > T18:15:20-0400 to T09:30:47Z > > > > Numbers are just the samples. But if I take a closure > look at them, -0400 needs to be replaced with "Z" > > > > Do you want to convert 12:00:00-04:00 to 08:00:00Z (the > same time instant in a different time zone) or to > 12:00:00Z? > > And are you using XSLT 1.0 or 2.0? > > Note: your date-time values are almost in ISO 8601 format, > except for the missing colon between hours and minutes in > the timezone offset. Was this difference deliberate? > > Michael Kay > Saxonica > > --~------------------------------------------------------------------ > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/ > or e-mail: <mailto:xsl-list-unsubscribe@xxxxxxxxxxxxxxxxxxxxxx> > --~--
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