Subject: Re: [xsl] question on EXSLT data partitioning From: Erwan AMOUREUX <erwan.amoureux@xxxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 21 Oct 2010 09:36:38 +0200 |
My mistake! sorry ----- Message d'origine ----- De : "Michael Kay" <mike@xxxxxxxxxxxx> @ : <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Envoyi : mercredi 20 octobre 2010 16:24 Objet : Re: [xsl] question on EXSLT data partitioning > >> For me it's logical >> When you use global variable, current node is root, so with the key ,it's the same thing and position is calculated with the root as initial context >> > > Whether it's logical or not, the specification is quite clear. In XSLT 1.0: > > the expression specified in the use attribute of the xsl:key element is > evaluated with x as the current node and with a node list containing > just x as the current node list > > So position() in the use expression returns 1. > > Michael Kay > Saxonica
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