Re: [xsl] Syntax on XML parser?

Subject: Re: [xsl] Syntax on XML parser?
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Thu, 02 Dec 2010 09:21:50 +0000
Saxon is an XSLT processor, not an XML parser. So you can't instantiate Saxon as a SAXBuilder.

You can instantiate Saxon as a JAXP TransformerFactory: for Saxon-HE the class name is net.sf.saxon.TransformerFactoryImpl. But since JAXP doesn't have support for XSLT 2.0 features, I would encourage you to use Saxon's s9api interface instead.

Michael Kay

On 02/12/2010 07:30, Jack Bush wrote:
Hi All,
What is the syntax to reference Saxon (9.1) parser when reading XML document?
Below is an example when using Xerces parser:
c SAXBuilder builder = new SAXBuilder("org.apache.xerces.parsers.SAXParser",
Also like to find out what is the default parser used by JAXP such as the
SAXBuilder builder = new SAXBuilder(false);

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