Re: [xsl] Syntax on XML parser?

Subject: Re: [xsl] Syntax on XML parser?
From: Jack Bush <netbeansfan@xxxxxxxxxxxx>
Date: Thu, 2 Dec 2010 04:28:28 -0800 (PST)
Thanks Michael for clarifying the differences between a parser &
transformation,B andB the functionality Saxon provide. So what is the default
parser when using SAXBuilder(false) without specifying a parser?

Thanks
again,

Jack


----- Original Message ----
From: Michael Kay
<mike@xxxxxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Sent: Thu, 2 December,
2010 8:21:50 PM
Subject: Re: [xsl] Syntax on XML parser?

Saxon is an XSLT
processor, not an XML parser. So you can't instantiate Saxon as 
a SAXBuilder.
You can instantiate Saxon as a JAXP TransformerFactory: for Saxon-HE the class
name is net.sf.saxon.TransformerFactoryImpl. But since JAXP doesn't have
support 
for XSLT 2.0 features, I would encourage you to use Saxon's s9api
interface 
instead.

Michael Kay
Saxonica

On 02/12/2010 07:30, Jack Bush
wrote:
> Hi All,
>B  What is the syntax to reference Saxon (9.1) parser when
reading XML document?
> Below is an example when using Xerces parser:
> cB 
B  SAXBuilder builder = new 
SAXBuilder("org.apache.xerces.parsers.SAXParser",
> false);
>B  Also like to find out what is the default parser used by JAXP
such as the
> following:
>B  B  B  B  SAXBuilder builder = new
SAXBuilder(false);
>B  Thanks,
> Jack
> 
> 
> 
> 
>
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