[xsl] table formating

["Szabo, Patrick \(LNG-VIE\)" <patrick.szabo@xxxxxxxxxxxxx>]

Hi,

Again This have to ask you people for help because I'm stuck.

This is an abstract of what my input looks like:

<row>
    <cell>
     <absatz>Sozialversicherung (1.650,00 * 18,07 %)</absatz>
    </cell>
    <cell index="3"> </cell>
    <cell> </cell>
    <cell index="6">
     <absatz>298.16</absatz>
    </cell>
</row>

So the index of a <cell> says what its position in a <row> should be.
My desired output is:

<row>
    <cell>
     <absatz>Sozialversicherung (1.650,00 * 18,07 %)</absatz>
    </cell>
    <cell></cell>
    <cell index="3"> </cell>
    <cell> </cell>
    <cell></cell>
    <cell index="6">
     <absatz>298.16</absatz>
    </cell>
</row>

NOTE: It's not sure that there are always 2 cells with @index. Could be
more or less too.

I've tried this:
<xsl:template match="cell[@index]">
  <xsl:variable name="prec_cells"
select="xs:integer(count(preceding-sibling::cell[not(@index)]) +
sum(preceding-sibling::cell/@index))"/>

	<xsl:for-each select="1 to xs:integer((@index - 1) -
$prec_cells)">
		<entry>
			<absatz/>
		</entry>
	</xsl:for-each>
		<entry>
			<xsl:apply-templates/>
		</entry>
</xsl:template>

Unfortunately this only works for 1 <cell> with @index per <row>.

Can anyone tell me how to solve that ?!

Kind regards

. . . . . . . . . . . . . . . . . . . . . . . . . .
Patrick Szabo
 XSLT-Entwickler
LexisNexis
Marxergasse 25, 1030 Wien

mailto:patrick.szabo@xxxxxxxxxxxxx
Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146