Re: [xsl] Grouping siblings according to attribute sequence

[David Carlisle <davidc@xxxxxxxxx>]

On 08/04/2011 23:09, Christian Sestier wrote:
> <terms><sequence>  <value>THREE/TWO/ONE</value></sequence><sequence>  <value>THREE BIS/TWO BIS/ONE BIS</value></sequence><sequence>  <value>THREE TER/TWO BIS/ONE BIS</value></sequence><sequence><value>ONE FOURTH</value></terms>


 saxon9 ter.xml ter.xsl
<terms>
   <sequence>
      <value>THREE/TWO/ONE</value>
   </sequence>
   <sequence>
      <value>THREE BIS/TWO BIS/ONE BIS</value>
   </sequence>
   <sequence>
      <value>THREE TER/TWO BIS/ONE BIS</value>
   </sequence>
   <sequence>
      <value>ONE FOURTH</value>
   </sequence>
</terms>


<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output indent="yes" omit-xml-declaration="yes"/>

<xsl:template match="terms">
<terms>
<xsl:for-each-group  select="term" group-starting-with="term[@level=1]">
<xsl:variable name="l" select="current-group()[last()]/@level"/>
<xsl:for-each select="current-group()[@level=$l]">
<sequence>
<value>
<xsl:value-of select="value,reverse(current-group()[@level!=$l]/value)" 
separator="/"/>
</value>
</sequence>
</xsl:for-each>
</xsl:for-each-group>
</terms>
</xsl:template>
</xsl:stylesheet>

David