RE: [xsl] Access XML from the URL and put in different file

[Shashank Jain <shashankjain@xxxxxxxx>]

===Plain text===

Hello All,

 

Following is the test xml I am working on

 

<Description>

      <core
resource="http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml"/>

      <core
resource="http://xyz.com/E4E0EF48-030F-4ACE-B15E-E923AC582A6B/viewas/xml"/>

      <core
resource="http://xyz.com/9808A0E2-5678-435F-8C89-5B7C8C27E380/viewas/xml"/>

      <core
resource="http://xyz.com/80E137ED-E8CC-4B14-AC47-E437D8E91BBA/viewas/xml"/>

      <core
resource="http://xyz.com/97337AAC-81CF-4DD8-9C8F-B06744B13753/viewas/xml"/>

      <core
resource="http://xyz.com/114F7C46-C207-49BE-96D1-B5E4314342B9/viewas/xml"/>

<Description>

 

The value of resource attribute is a link to the XML
document.

I need to write an XSLT which creates 6 different output
file (as there are 6 <core>), and every output file should have their
respective XML.

 

=========

This is the test.xslt I wrote

<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2005/xpath-functions";>

      <xsl:output
method="xml" version="1.0" encoding="UTF-8"
indent="yes" name="xml"/>

      <xsl:template
match="/">

            <xsl:for-each
select="//core">

                  <xsl:variable
name="filename"
select="concat('output1/',substring(substring-after(@*:resource,'xyz.com/'),1
,5),'.xml')"/>

                  <xsl:value-of
select="$filename"/>

                  <!--
Creating  -->

                  <xsl:result-document
href="{$filename}" format="xml">

                        <xsl:value-of
select="@*:resource"/>

                  </xsl:result-document>

            </xsl:for-each>

      </xsl:template>

</xsl:stylesheet>

===========

I was able to get 6 different xml files, but they were
having the value of the respective resource attribute, not the whole XML.

 

 

Output

========

<?xml version="1.0"
encoding="UTF-8"?>

http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml

 

Required output is to get the whole XML, which appears
when the link is clicked/navigated.

 

Is there any way I can achieve this using XSLT.

 

Thanks,

Shashank Jain
----------------------------------------
> From: shashankjain@xxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Date: Wed, 13 Apr 2011 12:15:39 -0500
> Subject: [xsl] Access XML from the URL and put in different file
>
>
> Hello All,
> Following is the test xml I am working on
>
> The value of resource attribute is a link to the XML document. I need to
write an XSLT which creates 6 different output file (as there are 6 ), and
every output file should have their respective XML.
> =========This is the test.xslt I wrote           ===========I was able to
get 6 different xml files, but they were having the value of the respective
resource attribute, not the whole XML.
>
>
Output========http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml
> Required output is to get the whole XML, which appears when the link is
clicked/navigated.
> Is there any way I can achieve this using XSLT.
> Thanks,Shashank Jain