Re: [xsl] Select a node only if its previous siblings have specific attributes

[Brandon Ibach <brandon.ibach@xxxxxxxxxxxxxxxxxxx>]

I'm not sure I'm completely clear on your requirement, but try this:

//data[@result = '9'][not(preceding-sibling::data[@result != '10' and
@result != '11'])][last()]

-Brandon :)


On Fri, Apr 15, 2011 at 1:40 PM, Philipp Kursawe <phil.kursawe@xxxxxxxxx>
wrote:
> Hello,
>
> a node with @result='9' should be select if one of its previous
> siblings has @result=10 or @result=11. Only the most recent node with
> @result=9 should be selected.
>
> given the following examples:
>
> <root>
> <data result="11"/>
> <data result="10"/>
> <data result="9"/>
> </root>
> Should select data[3]
>
> <root>
> <data result="11"/>
> <data result="5"/>
> <data result="9"/>
> </root>
> Should not select any node, because one of data[3] prev siblings has
> @result != 10|11
>
> <root>
> <data result="11"/>
> <data result="9"/>
> <data result="5"/>
> <data result="9"/>
> </root>
> Should select data[2] not data[4] because data[4] has previous
> siblings with @result != 10|11
>
> How would the XPath selector look like? Basically i need to find the
> first() (or last()?) node whose previous siblings do not have
> @result=10|11
>
> Thanks for your help!
> Phil