Subject: Re: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0 From: Wolfhart Totschnig <wolfhart@xxxxxxxxxxxxx> Date: Wed, 06 Jul 2011 15:40:27 -0500 |
How about this (not very cool):
test="concat(path/person/first, '|', path/person/first, '|', path/person/first) = concat(first, '|', middle, '|', last)
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