Re: [xsl] basename string sort and group

[Martin Honnen <Martin.Honnen@xxxxxx>]

davep wrote:
> Given input such as
> <fonts>
> <entry
> href="/apps/jdk/lib/fonts/LucidaTypewriterRegular.ttf">Lucida</entry>
> <entry href="/apps/jdk/lib/fonts/LucidaTypewriterBold.ttf">Lucida</entry>
> <entry
> href="/apps/jdk/lib/oblique-fonts/LucidaSansDemiOblique.ttf">Lucida</entry>
> </fonts>
>
> I want to sort and group by directory, for an output such as
>
> <fonts>
> <dir href="/apps/jdk/lib/fonts">
> <entry href="LucidaTypewriterRegular.ttf">Lucida</entry>
> <entry href="LucidaTypewriterBold.ttf">Lucida</entry>
> </dir>
> <dir href="/apps/jdk/lib/oblique-fonts">
> <entry href="LucidaSansDemiOblique.ttf">Lucida</entry>
> </dir>
>
> etc.
>
> I.e. Isolate the directories, then group all entries within that directory.


  <xsl:template match="fonts">
    <xsl:copy>
      <xsl:for-each-group select="entry"
        group-by="string-join(tokenize(@href, '/')[position() lt 
last()], '/')>
          <dir href="{current-grouping-key()}">
            <xsl:apply-templates select="current-group()"/>
          </dir>
      </xsl:for-each-group>
     </xsl:copy>
   </xsl:template

   <xsl:template match="entry">
     <entry href="{tokenize(@href, '/')[last()]}">
        <xsl:value-of select="."/>
     </entry>
   </xsl:template>

Untested.


--

	Martin Honnen --- MVP Data Platform Development
	http://msmvps.com/blogs/martin_honnen/