Re: [xsl] basename string sort and group

Subject: Re: [xsl] basename string sort and group
From: davep <davep@xxxxxxxxxxxxx>
Date: Sat, 03 Sep 2011 13:51:56 +0100
On 09/03/2011 01:10 PM, Martin Honnen wrote:
davep wrote:
Given input such as
<fonts>
<entry
href="/apps/jdk/lib/fonts/LucidaTypewriterRegular.ttf">Lucida</entry>
<entry href="/apps/jdk/lib/fonts/LucidaTypewriterBold.ttf">Lucida</entry>
<entry
href="/apps/jdk/lib/oblique-fonts/LucidaSansDemiOblique.ttf">Lucida</entry>


</fonts>

I want to sort and group by directory, for an output such as

<fonts>
<dir href="/apps/jdk/lib/fonts">
<entry href="LucidaTypewriterRegular.ttf">Lucida</entry>
<entry href="LucidaTypewriterBold.ttf">Lucida</entry>
</dir>
<dir href="/apps/jdk/lib/oblique-fonts">
<entry href="LucidaSansDemiOblique.ttf">Lucida</entry>
</dir>

etc.

I.e. Isolate the directories, then group all entries within that directory.


<xsl:template match="fonts">
<xsl:copy>
<xsl:for-each-group select="entry"
group-by="string-join(tokenize(@href, '/')[position() lt last()], '/')>
<dir href="{current-grouping-key()}">
<xsl:apply-templates select="current-group()"/>
</dir>
</xsl:for-each-group>
</xsl:copy>
</xsl:template


<xsl:template match="entry">
<entry href="{tokenize(@href, '/')[last()]}">
<xsl:value-of select="."/>
</entry>
</xsl:template>

Untested.



Thanks Martin. Appreciated.




regards


--
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk

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