[xsl] Position() Function Using Filter

[Lighton Phiri <lighton.phiri@xxxxxxxxx>]

I am trying to figure out how to get the position of a particular node
after apply a filter. I am able to get the result after using the
XPath below, however, I can't seem to figure out how to get the
position of that node.

bpage = ASTRO_00007.JPG
books/book[substring-after(substring-after(substring-after(text(),
'/'), '/'), '/')=$bpage]

<books>
<book>books/physics/astronomy/ASTRO_00002.JPG</>
<book>books/physics/astronomy/ASTRO_00003.JPG</>
<book>books/physics/astronomy/ASTRO_00004.JPG</>
<book>books/physics/astronomy/ASTRO_00005.JPG</>
<book>books/physics/astronomy/ASTRO_00006.JPG</>
<book>books/physics/astronomy/ASTRO_00007.JPG</>
<book>books/physics/astronomy/ASTRO_00008.JPG</>
<book>books/physics/astronomy/ASTRO_00009.JPG</>
<book>books/physics/astronomy/ASTRO_00010.JPG</>
</books>

Lighton Phiri
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