Subject: Re: [xsl] Position() Function Using Filter From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Fri, 28 Oct 2011 16:02:05 +0200 |
I am trying to figure out how to get the position of a particular node after apply a filter. I am able to get the result after using the XPath below, however, I can't seem to figure out how to get the position of that node.
bpage = ASTRO_00007.JPG books/book[substring-after(substring-after(substring-after(text(), '/'), '/'), '/')=$bpage]
<books> <book>books/physics/astronomy/ASTRO_00002.JPG</> <book>books/physics/astronomy/ASTRO_00003.JPG</> <book>books/physics/astronomy/ASTRO_00004.JPG</> <book>books/physics/astronomy/ASTRO_00005.JPG</> <book>books/physics/astronomy/ASTRO_00006.JPG</> <book>books/physics/astronomy/ASTRO_00007.JPG</> <book>books/physics/astronomy/ASTRO_00008.JPG</> <book>books/physics/astronomy/ASTRO_00009.JPG</> <book>books/physics/astronomy/ASTRO_00010.JPG</> </books>
<xsl:number/> can help to find the "position" of a node relative to other nodes.
Martin Honnen --- MVP Data Platform Development http://msmvps.com/blogs/martin_honnen/
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