Subject: Re: [xsl] position() function in loop provides only 1 From: Michel Hendriksen <michel.hendriksen@xxxxx> Date: Wed, 11 Apr 2012 14:06:15 +0200 |
In for each the context will switch, so position will be reset inside You could keep position in a variable if you need it. Michel On Wed, Apr 11, 2012 at 1:57 PM, henry human <henry_human@xxxxxxxx> wrote: > Hi all > I use the positon() funciton to build a counter. > I use it in a for-each loop under another for-each. The result is but ever 1. > Strange, but in the same document in the first for-each loop it works fine (bellow is first loop, for-each select="Item) > sample document look like this: > > > <xsl:for-each select="Item"> > <it> > <xsl:value-of select=" position()"> > > </it><it> > <xsl:value-of select=" position()"> > </it> > ........ > <it> > //position = 113 > </it> > </xsll:for-each> > <xsl:for-each select="InvoiceLine"> > <xsl:for-each select="taxtotal"> > .... > <xsl:value-of select=" position()"> > </xsll:for-each> > </xsll:for-each> > ------ > > <invoiceLine> > <taxtoatl> > </taxtoal> > > <taxtotal> > </taxtotal> > ........... > </invoiceLine> > kind regards > Henry
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