Subject: Re: [xsl] position() function in loop provides only 1 From: Michael Kay <mike@xxxxxxxxxxxx> Date: Wed, 11 Apr 2012 14:20:00 +0100 |
Michael Kay Saxonica
I now that the position() reset after a loop is ended and I am not expecting some thing else . In my case the position () provides correctly the POSITION for each loop in the FIRST loop but in the other loop (xsl:for-each select="taxtotal) the position() function provides ever ONE and does not increment!!! Regarding number function I do not now how to use it here. and I think you are wrong, in XSLT you canbt save value to a variable and use it global! Kind regards
----- UrsprC<ngliche Message -----
Von: Michel Hendriksen<michel.hendriksen@xxxxx>
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
CC:
Gesendet: 14:06 Mittwoch, 11.April 2012
Betreff: Re: [xsl] position() function in loop provides only 1
In for each the context will switch, so position will be reset inside You could keep position in a variable if you need it.
Michel
On Wed, Apr 11, 2012 at 1:57 PM, henry human<henry_human@xxxxxxxx> wrote:Hi all I use the positon() funciton to build a counter. I use it in a for-each loop under another for-each. The result is but ever 1. Strange, but in the same document in the first for-each loop it works fine (bellow is first loop, for-each select="Item) sample document look like this:
<xsl:for-each select="Item"> <it> <xsl:value-of select=" position()">
</it><it> <xsl:value-of select=" position()"> </it> ........ <it> //position = 113 </it> </xsll:for-each> <xsl:for-each select="InvoiceLine"> <xsl:for-each select="taxtotal"> .... <xsl:value-of select=" position()"> </xsll:for-each> </xsll:for-each> ------
<invoiceLine> <taxtoatl> </taxtoal>
<taxtotal> </taxtotal> ........... </invoiceLine> kind regards Henry
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