Re: [xsl] XPath 1.0 Expression to Test for 3 Digit Number

[Michael Kay <mike@xxxxxxxxxxxx>]

Dimitre's solution will accept '0500', mine will not. I took the 
requirement to have three digits literally.

Michael Kay
Saxonica

On 08/05/2012 21:31, Dimitre Novatchev wrote:
> floor(.) = number(.) and number(.)>  99 and not(number(.)>  999)
>
>
> Cheers,
> Dimitre
>
> On Tue, May 8, 2012 at 1:15 PM, Michael Kay<mike@xxxxxxxxxxxx>  wrote:
> > translate(., '0123456789', '9999999999') = '999' and number(.)>  99
> >
> > Michael Kay
> > Saxonica
> >
> >
> > On 08/05/2012 21:07, Don Smith wrote:
> > > I need an XPath 1.0 expression that will test a node and return a
> > > boolean if the node content is a 3 digit number (i.e., 100-999) and
> > > false if it's anything else.
> > >
> > > The catch is this expression won't
> > > be in a transformation so I can't use variables or other additional
> > > constructs. All I get is one expression. I've tried this
> > >
> > > *[(string(number(.)) !='NaN')]
> > >
> > >
> > > and
> > >   obtained the number that I need. But I can't get any sort of compare to
> > >   work that makes the number be more than 99 and less than 1,000.
> > >
> > > Thanks
> > >
> > > Don