Re: [xsl] XPath 1.0 Expression to Test for 3 Digit Number

[Vasu Chakkera <vasucv@xxxxxxxxx>]

Ken,
Your solution is correct.Dint mean to poke  your solution .. sorry
String length is still a tricky thing to do for numbers ( IMO )
Vasu

On 27 May 2012 11:47, G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> wrote:
> At 2012-05-27 09:14 +0100, Vasu Chakkera wrote:
>>
>> string-length could be tricky if the number 999 is represented as 00999.
>
>
> I'm not sure about your concern because I already accommodated that
> situation with my answer:
>
>  string-length(string(number(.)))=3]
>
> The number cast will ensure that any leading insignificant zeroes won't
> impact the string's length.
>
> Is there something I'm missing that prompted you to write?
>
> . . . . . . . . . Ken
>
>
>> On 8 May 2012 21:14, G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> wrote:
>> > At 2012-05-08 13:07 -0700, Don Smith wrote:
>> >>
>> >> I need an XPath 1.0 expression that will test a node and return a
>> >> boolean if the node content is a 3 digit number (i.e., 100-999) and
>> >> false if it's anything else.
>> >>
>> >> The catch is this expression won't
>> >> be in a transformation so I can't use variables or other additional
>> >> constructs. All I get is one expression. I've tried this
>> >>
>> >> *[(string(number(.)) !='NaN')]
>> >>
>> >>
>> >> and
>> >>  obtained the number that I need. But I can't get any sort of compare
>> >> to
>> >>  work that makes the number be more than 99 and less than 1,000.
>> >
>> >
>> > Did you try just checking its length?  Note I use a different comparison
>> > to
>> > ensure the value is, itself, a number at all.
>> >
>> > *[number(.)=number(.) and string-length(string(number(.)))=3]
>> >
>> > I hope this helps.
>> >
>> > . . . . . . . . Ken
>
>
>
>
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--
Vasu Chakkera
NodeLogic Limited
Oxford
www.node-logic.com
==============