Subject: Re: [xsl] XPath 1.0 Expression to Test for 3 Digit Number From: Vasu Chakkera <vasucv@xxxxxxxxx> Date: Sun, 27 May 2012 09:14:56 +0100 |
string-length could be tricky if the number 999 is represented as 00999. On 8 May 2012 21:14, G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> wrote: > At 2012-05-08 13:07 -0700, Don Smith wrote: >> >> I need an XPath 1.0 expression that will test a node and return a >> boolean if the node content is a 3 digit number (i.e., 100-999) and >> false if it's anything else. >> >> The catch is this expression won't >> be in a transformation so I can't use variables or other additional >> constructs. All I get is one expression. I've tried this >> >> *[(string(number(.)) !='NaN')] >> >> >> and >> obtained the number that I need. But I can't get any sort of compare to >> work that makes the number be more than 99 and less than 1,000. > > > Did you try just checking its length? Note I use a different comparison to > ensure the value is, itself, a number at all. > > *[number(.)=number(.) and string-length(string(number(.)))=3] > > I hope this helps. > > . . . . . . . . Ken > > > -- > Public XSLT, XSL-FO, UBL and code list classes in Europe -- Oct 2012 > Contact us for world-wide XML consulting and instructor-led training > Free 5-hour lecture: http://www.CraneSoftwrights.com/links/udemy.htm > Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ > G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx > Google+ profile: https://plus.google.com/116832879756988317389/about > Legal business disclaimers: http://www.CraneSoftwrights.com/legal > -- Vasu Chakkera NodeLogic Limited Oxford www.node-logic.com ==============
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