Subject: Re: [xsl] xsl:include From: Michel Hendriksen <michel.hendriksen@xxxxx> Date: Tue, 19 Jun 2012 17:31:05 +0200 |
I think you need a resolver if you get the include from some other place. Otherwise the default resolver should work. On Tue, Jun 19, 2012 at 5:28 PM, Ming Yu <my600080@xxxxxxxxx> wrote: > In my stylesheet, I need to use xsl:include to include another stylesheet libraries I wrote. What's the best way to resolve the url of the xsl:include? > > It seems that some people are trying to use URIResolver. But I don't seem to be able to put the pieces together. Do I need to write my own URIResolver? How can I call the URIResolver? Do I need to put information in my beans.xml file? > > Or is it possible to include in the java classpath? > > My goal is to use a url that's relative to the parent xslt in the xsl:include. > > i.e. <xsl:include href="mylibrary.xsl" />. And the mylibrary.xsl is in the same directory as the parent xslt which includes the mylibary.xsl. > > Thanks a lot! > > Ming
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