Subject: Re: [xsl] extracting and removing an element nested at different levels From: "Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx> Date: Wed, 05 Sep 2012 00:24:19 +0200 |
<xsl:template match="List"> <xsl:copy> <xsl:apply-templates select=".//Item"/> </xsl:copy> </xsl:template>
<xsl:template match="Item"> <xsl:copy> <xsl:apply-templates mode="suppress-item"/> </xsl:copy> </xsl:template>
<xsl:template match="* | @*" mode="#all"> <xsl:copy> <xsl:apply-templates select="@*, node()" mode="#current"/> </xsl:copy> </xsl:template>
<xsl:template match="List"> <xsl:copy> <xsl:for-each select=".//Item"> <xsl:copy> <xsl:apply-templates/> </xsl:copy> </xsl:for-each> </xsl:copy> </xsl:template>
<xsl:template match="* | @*"> <xsl:copy> <xsl:apply-templates select="@*, node()" mode="#current"/> </xsl:copy> </xsl:template>
I have XML consisting of <Item> elements that have nested <Item> elements at various depths within the tree, in its simplest form something like:
<List> <Item> <ElementA> <Item> <ElementB/> </Item> </ElementA> </Item> </List>
That I want to render as:
<List> <Item> <ElementA/> </Item> <Item> <ElementB/> </Item> </List>
Is there a general technique I can use to remove nested <Item> elements whatever their depth and place all <Item> elements at the same level within the <List>? Thanks, Mark
-- Gerrit Imsieke Geschdftsf|hrer / Managing Director le-tex publishing services GmbH Weissenfelser Str. 84, 04229 Leipzig, Germany Phone +49 341 355356 110, Fax +49 341 355356 510 gerrit.imsieke@xxxxxxxxx, http://www.le-tex.de
Registergericht / Commercial Register: Amtsgericht Leipzig Registernummer / Registration Number: HRB 24930
Geschdftsf|hrer: Gerrit Imsieke, Svea Jelonek, Thomas Schmidt, Dr. Reinhard Vvckler
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