Subject: Re: [xsl] extracting and removing an element nested at different levels From: "Mark" <mark@xxxxxxxxxxxx> Date: Tue, 4 Sep 2012 15:28:58 -0700 |
Thanks, I'll work through these tonight. Appreciate your help. Mark
Two possible solutions using identity templates. The first one uses a dedicated mode for the nested items:
<xsl:template match="List"> <xsl:copy> <xsl:apply-templates select=".//Item"/> </xsl:copy> </xsl:template>
<xsl:template match="Item"> <xsl:copy> <xsl:apply-templates mode="suppress-item"/> </xsl:copy> </xsl:template>
<xsl:template match="* | @*" mode="#all"> <xsl:copy> <xsl:apply-templates select="@*, node()" mode="#current"/> </xsl:copy> </xsl:template>
<xsl:template match="List"> <xsl:copy> <xsl:for-each select=".//Item"> <xsl:copy> <xsl:apply-templates/> </xsl:copy> </xsl:for-each> </xsl:copy> </xsl:template>
<xsl:template match="* | @*"> <xsl:copy> <xsl:apply-templates select="@*, node()" mode="#current"/> </xsl:copy> </xsl:template>
Both wont leave an empty ElementA though because of the contained text nodes.
I have XML consisting of <Item> elements that have nested <Item> elements at various depths within the tree, in its simplest form something like:
<List> <Item> <ElementA> <Item> <ElementB/> </Item> </ElementA> </Item> </List>
That I want to render as:
<List> <Item> <ElementA/> </Item> <Item> <ElementB/> </Item> </List>
Is there a general technique I can use to remove nested <Item> elements whatever their depth and place all <Item> elements at the same level within the <List>? Thanks, Mark
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