Subject: Re: [xsl] Re: position last and attributes From: Wolfgang Laun <wolfgang.laun@xxxxxxxxx> Date: Wed, 26 Sep 2012 13:26:32 +0200 |
string-join() ? -W On 26/09/2012, Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx> wrote: > On Thu, Sep 20, 2012 at 7:13 AM, Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx> > wrote: >> It would seem (somewhat paradoxically) that given the definition of >> position() and last() they could be applied to @* which is >> intrinsically unordered. > > So seeking to output all the attributes of an element comma separated > (by all means correct me if I miss the obvious). > > If I have done apply-templates select="@*" and have > > <xsl:template match="@*"> > < code to output the attribute> > <!-- do I put a comma or not --> > <xsl:if test=". is ../@*[last()]>,</xsl:if> > > the specification doesn't guarantee that ../@* is in the same order of > the node-set returned by @* when the apply-templates was done. > > So either I have to put the @* in a variable and do my if test on that > to ensure I am dealing with the same node-set or I match on the > parent element instead of @* and for-each through @* and decide where > to put my commas that way. > > Or have I got that wrong.
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