Subject: [xsl] Re: position last and attributes From: Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx> Date: Wed, 26 Sep 2012 12:19:11 +0100 |
On Thu, Sep 20, 2012 at 7:13 AM, Ihe Onwuka <ihe.onwuka@xxxxxxxxxxxxxx> wrote: > It would seem (somewhat paradoxically) that given the definition of > position() and last() they could be applied to @* which is > intrinsically unordered. So seeking to output all the attributes of an element comma separated (by all means correct me if I miss the obvious). If I have done apply-templates select="@*" and have <xsl:template match="@*"> < code to output the attribute> <!-- do I put a comma or not --> <xsl:if test=". is ../@*[last()]>,</xsl:if> the specification doesn't guarantee that ../@* is in the same order of the node-set returned by @* when the apply-templates was done. So either I have to put the @* in a variable and do my if test on that to ensure I am dealing with the same node-set or I match on the parent element instead of @* and for-each through @* and decide where to put my commas that way. Or have I got that wrong.
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