Subject: Re: [xsl] Saxon 9.4 <bold></bold> Transformed to (newline)</bold> Problem From: Michael Kay <mike@xxxxxxxxxxxx> Date: Tue, 15 Jan 2013 17:03:51 +0000 |
Michael Kay Saxonica
List members,
Due to some batch processing, some of my input XML may have empty elements.
Here is some sample XML: <level1> <para> Here is some text inside a para tag. <bold></bold> Note that the 'bold' element before the word Note is empty. I would like it to stay that way without the insertion of a newline.</para> </level1>
When I transform this XML, using Saxon 9.4, the <bold></bold> element is getting converted similar to the following: <level1> <para> Here is some text inside a para tag. <bold/> Note that the 'bold' element before the word Note is empty. I would like it to stay that way.</para> </level1>
The Problem: Due to further batch processing needs, I do not want the insertion of a newline before the <bold/> element, which is being created after running an XSLT transformation on the sample XML above. (XMLSpy does not insert the newline, by the way, but I want to use Saxon for my transformation.) In my xsl file I do not have an explicit template match for the 'bold' element.
My XSL: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:mcc="http://www.municode.com/xslt">
<xsl:strip-space elements="*" /> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<!-- To Get: {$InputDocPath} --> <xsl:include href="./MCC_LIB.xsl"/>
<xsl:template match="/"> <xsl:result-document href="{$InputDocPath}/Book_ALL.xml"> <xsl:apply-templates select="node()" /> </xsl:result-document> </xsl:template> <xsl:template match="book"> <xsl:element name="book"> <xsl:element name="bookinfo"> <xsl:element name="title"></xsl:element> <xsl:element name="subtitle"></xsl:element> </xsl:element> <xsl:apply-templates select="node()"/> </xsl:element> </xsl:template>
<xsl:template match="level1|level2|level3|level4|level5|level6"> <xsl:copy-of select="./node()" copy-namespaces="no" /> </xsl:template>
<!-- CATCH-ALL ==================================================== --> <xsl:template match="@*|node()"> <xsl:copy-of select="./node()" copy-namespaces="no" /> </xsl:template> </xsl:stylesheet>
Looking in the Saxon documentation, I was not able to find a switch to control the transformation behavior that changes the <bold></bold> to (newline)<bold/>.
I'd rather not use XMLSpy since all my other batch transformations are using Saxon. If there is a configuration switch for Saxon, could someone direct me where I may learn about it.
Or, would it be more practical to write a template to remove the "empty" <bold></bold> element, or better yet, remove all empty elements? I don't know how this would be written, and would appreciate any insights someone may offer.
Kind regards,
Raymond Lillibridge Sr. Software Engineer rlillibridge@xxxxxxxxxxxx Municipal Code Corporation | Facebook | Twitter
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