Subject: Re: [xsl] Only child test From: Michael Kay <mike@xxxxxxxxxxxx> Date: Thu, 10 Oct 2013 07:33:48 +0100 |
count(../* gt 1) or if you know that you're processing all siblings at the time, last() gt 1 Michael Kay Saxonica On 10 Oct 2013, at 05:38, Karl Stubsjoen wrote: > Just curious how other's might approach a test to determine if the > current node is *not* an only child. This works fine but it feels a > little heavy to me. Thoughts? > > <xsl:if test="(count(preceding-sibling::*) + > count(following-sibling::*)) > 1"> > <hr/> > </xsl:if>
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