Subject: Re: [xsl] Only child test From: Michael Kay <mike@xxxxxxxxxxxx> Date: Thu, 10 Oct 2013 10:02:10 +0100 |
On 10 Oct 2013, at 09:42, PQQP5QP;P0P2 P!P5P4P>P2 wrote: > can be test="../*[2]" faster? A processor with a decent optimizer (e.g. Saxon) will do that rewrite for you. Michael Kay Saxonica > > 2013/10/10 Michael Kay <mike@xxxxxxxxxxxx>: >> count(../* gt 1) >> >> or if you know that you're processing all siblings at the time, >> >> last() gt 1 >> >> Michael Kay >> Saxonica >> >> >> On 10 Oct 2013, at 05:38, Karl Stubsjoen wrote: >> >>> Just curious how other's might approach a test to determine if the >>> current node is *not* an only child. This works fine but it feels a >>> little heavy to me. Thoughts? >>> >>> <xsl:if test="(count(preceding-sibling::*) + >>> count(following-sibling::*)) > 1"> >>> <hr/> >>> </xsl:if>
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