[xsl] how to avoid hardcoding xpath-default-namespace in xs

Hopefully the compilation at the bottom of this
message  should make clear what I'm after.
But to be explicit, what do I put after

xpath-default-namespace=

in the <xsl:stylesheet ... /> to retrieve the namespace used
in source document.

-regards,
Larry

---{compilation---
compilation; default-directory: "/home/evansl/prog_dev/xslt/sandbox/" -*-
Compilation started at Fri Apr 11 17:05:57

make -k
cat ./inp/defaultns.html
<!--?xml version="1.0" encoding="utf-8"?-->
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
<!--Example of using default namespace -->
<html xml:lang="en" xmlns="xxx" lang="en">
  <head>
    <title>default namespace .html</title>
  </head>
  <body>
    <address>Nowhere</address>
  </body>
</html>
cat ./xfm/defaultns.xml
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
 version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
 xpath-default-namespace="xxx"
><!--How to avoid this hardcoding of xpath-default-namespace?-->
<xsl:template match="html">
  <xsl:copy-of select="."/>
  <xsl:text>
  </xsl:text>
  <xsl:text>@lang=</xsl:text>
  <xsl:value-of select="@lang"/>
  <xsl:text>
  </xsl:text>
  <xsl:text>@xmlns=</xsl:text>
  <xsl:value-of select="namespace::*[name() eq '']"/>
</xsl:template>

</xsl:stylesheet> /home/evansl/dwnlds/oracle/jdk_8_nb_8/install.dir/jdk1.8.0/bin/java -cp /home/evansl/dwnlds/saxon/9.5/saxon9he.jar net.sf.saxon.Transform -xsltversion:2.0 -T -s:inp/defaultns.html -xsl:./xfm/defaultns.xml -o:out/defaultns.defaultns.html <trace saxon-version="9.5.1.5" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <source node="/html" line="5" file="defaultns.html"> <xsl:template match="html" line="7" module="defaultns.xml"> <xsl:copy-of line="8" module="defaultns.xml"> </xsl:copy-of> <xsl:text line="9" module="defaultns.xml"> </xsl:text> <xsl:text line="11" module="defaultns.xml"> </xsl:text> <xsl:value-of line="12" module="defaultns.xml"> </xsl:value-of> <xsl:text line="13" module="defaultns.xml"> </xsl:text> <xsl:text line="15" module="defaultns.xml"> </xsl:text> <xsl:value-of line="16" module="defaultns.xml"> </xsl:value-of> </xsl:template> </source> </trace> cat out/defaultns.defaultns.html <?xml version="1.0" encoding="UTF-8"?><html xmlns="xxx" xml:lang="en" lang="en"><head><title>default namespace .html</title></head><body> <address>Nowhere</address> </body></html> @lang=en @xmlns=xxx Compilation finished at Fri Apr 11 17:05:59

---}compilation---

<- Previous	Index	Next ->
[xsl] [ANN] Published: XPath 3.0, X, Liam R E Quin	Thread	Re: [xsl] how to avoid hardcoding x, David Carlisle
Re: [xsl] module extensibility, Liam R E Quin	Date	Re: [xsl] how to avoid hardcoding x, David Carlisle
	Month

<-prev [Thread] next->	<-prev [Date] next->
Month Index \| List Home

[xsl] how to avoid hardcoding xpath-default-namespace in xsl:stylesheet?