Re: [xsl] Increasing sequence ?

Subject: Re: [xsl] Increasing sequence ?
From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Thu, 26 Mar 2015 02:42:05 -0000
On Wed, Mar 25, 2015 at 11:51 AM, Wolfgang Laun
wolfgang.laun@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
>> not($seq[2])  or $seq[1] lt $seq[2]  and  increasing(subsequence($seq, 2))
> It would appear that this makes -1,0,2,1 an ascending sequence. I dislike
> this "empty-is-false trick" - once in a while you get bitten.
> count($seq) &lt; 2 or ...

Yes, good to remind that we are dealing with items -- not just nodes.

> count($seq) &lt; 2 or ...

No, the idea is to avoid count, as this may add the time for one
unnecessary pass over the sequence. And the solution can be adjusted

  <xsl:function name="my:increasing" as="xs:boolean">
    <xsl:param name="pSeq" as="item()*"/>

    <xsl:sequence select=
       $pSeq[1] lt $pSeq[2]  and  my:increasing(subsequence($pSeq, 2))"/>

Dimitre Novatchev
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