Subject: [xsl] Need xsl help From: "Rahul Singh rahulsinghindia15@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 8 Sep 2016 18:07:55 -0000 |
Hi. I have only one XML. and there <Nid> contains same data like 892828740. I want get the Id,Updateeddate,Nid for Contact based on Updateeddate if Nid has more then one same data. Below is my input, XSL, expected output Below is XML: <?xml version="1.0" encoding="UTF-8"?> <objects> <Contact> <Id>003j000001DQMkcAAH</Id> <Updateeddate>2016-09-08T10:31:24.000Z</Updateeddate> <Nid>892828740</Nid> </Contact> <Contact> <Id>003j000001DQMlXAAX</Id> <Updateeddate>2016-09-08T10:22:47.000Z</Updateeddate> <Nid>879284114</Nid> </Contact> <Contact> <Id>003j000001DQMlYAAX</Id> <Updateeddate>2016-09-08T10:22:47.000Z</Updateeddate> <Nid>882692370</Nid> </Contact> <Contact> <Id>003j000001DQMlZAAX</Id> <Updateeddate>2016-09-08T10:22:47.000Z</Updateeddate> <Nid>892828740</Nid> </Contact> </objects> Below in XSL: <xsl:stylesheet version="2.0" xmlns:xsl=" http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/> <xsl:template match="objects"> <xsl:if test="count(//Contact/Nid[(. = ../following-sibling::Contact/Nid)])"> <Nids> <Nid> <Id> <xsl:value-of select="//Contact/Nid[(. = ../following-sibling::Contact/Nid)]"/> </Id> <updateDate> <xsl:value-of select="//Updateeddate"/> </updateDate> <Nid/> </Nid> </Nids> </xsl:if> </xsl:template> </xsl:stylesheet> Expected output: <objects> <Contact> <Id>003j000001DQMkcAAH</Id> <Updateeddate>2016-09-08T10:31:24.000Z</Updateeddate> <Nid>892828740</Nid> </Contact> <Contact> <Id>003j000001DQMlXAAX</Id> <Updateeddate>2016-09-08T10:22:47.000Z</Updateeddate> <Nid>879284114</Nid> </Contact> <Contact> <Id>003j000001DQMlYAAX</Id> <Updateeddate>2016-09-08T10:22:47.000Z</Updateeddate> <Nid>882692370</Nid> </Contact> </objects>
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