Subject: [xsl] How to sort and compare with different element value in XSL From: "Rahul Singh rahulsinghindia15@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 9 Sep 2016 09:25:20 -0000 |
I have only one XML. and there <Nid> contains same data like 892828740. I want get the Id,LastModifiedDate,Nid for Contact based on updated LastModifiedDate if <Nid> has more then one same kind of data. Below is my Input data, XSL, expected output. But my code is not working fine Below is XML: <?xml version="1.0" encoding="UTF-8"?> <objects> <Contact> <Id>003j000001DQMkcAAH</Id> <LastModifiedDate>2016-09-08T10:31:24.000Z</LastModifiedDate> <Nid>892828740</Nid> </Contact> <Contact> <Id>003j000001DQMlXAAX</Id> <LastModifiedDate>2016-09-08T10:22:47.000Z</LastModifiedDate> <Nid>879284114</Nid> </Contact> <Contact> <Id>003j000001DQMlYAAX</Id> <LastModifiedDate>2016-09-08T10:22:47.000Z</LastModifiedDate> <Nid>882692370</Nid> </Contact> <Contact> <Id>003j000001DQMlZAAX</Id> <LastModifiedDate>2016-09-08T10:22:47.000Z</LastModifiedDate> <Nid>892828740</Nid> </Contact> </objects> Below in XSL: <xsl:stylesheet version="2.0" xmlns:xsl=" http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/> <xsl:template match="objects"> <xsl:if test="count(//Contact/Nid[(. = ../following-sibling::Contact/Nid)])"> <Nids> <Nid> <Id> <xsl:value-of select="//Contact/Nid[(. = ../following-sibling::Contact/Nid)]"/> </Id> <LastModifiedDate> <xsl:value-of select="//LastModifiedDate"/> </LastModifiedDate> <Nid/> </Nid> </Nids> </xsl:if> </xsl:template> </xsl:stylesheet> Expected output: <objects> <Contact> <Id>003j000001DQMkcAAH</Id> <LastModifiedDate>2016-09-08T10:31:24.000Z</LastModifiedDate> <Nid>892828740</Nid> </Contact> <Contact> <Id>003j000001DQMlXAAX</Id> <LastModifiedDate>2016-09-08T10:22:47.000Z</LastModifiedDate> <Nid>879284114</Nid> </Contact> <Contact> <Id>003j000001DQMlYAAX</Id> <LastModifiedDate>2016-09-08T10:22:47.000Z</LastModifiedDate> <Nid>882692370</Nid> </Contact> </objects>
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