Re: [xsl] How to sort and compare with different element value in XSL

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 09.09.2016 11:25, Rahul Singh rahulsinghindia15@xxxxxxxxx wrote:
> I have only one XML. and there <Nid> contains same data like 892828740.
> I want get the Id,LastModifiedDate,Nid for Contact based on updated
> LastModifiedDate if <Nid> has more then one same kind of data. Below is
> my Input data, XSL, expected output. But my code is not working fine

Here is an enhancement of the stylesheet David posted after your last 
question:

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
	xmlns:xs="http://www.w3.org/2001/XMLSchema";>
	
	<xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>
	
	<xsl:strip-space elements="*"/>
	
	<xsl:template match="objects">
		<xsl:copy>
			<xsl:for-each-group select="Contact" group-by="Nid">
				<xsl:for-each select="current-group()">
					<xsl:sort select="xs:dateTime(LastModifiedDate)" order="descending"/>
					<xsl:if test="position() eq 1">
						<xsl:copy-of select="."/>
					</xsl:if>
				</xsl:for-each>
			</xsl:for-each-group>
		</xsl:copy>
	</xsl:template>
	
</xsl:stylesheet>